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A circular current loop of magnetic mome...

A circular current loop of magnetic moment `M` is in an arbitrary orientation in an external magnetic field `vec(B)`. The work done to rotate the loop by `30^(@)` about an axis perpendicular to its plane is `:`

A

MB

B

`sqrt3 (MB)/2`

C

`(MB)/2`

D

zero.

Text Solution

Verified by Experts

The correct Answer is:
d
If `theta` is the angle between magnetic moment `vec M` of the current loop and external magnetic field, then on rotating the current loop by some angle about an axis perpendicular to its plane, there will be no change in the value of `theta`. So, no work will be done in this case as work done is given by
`W = MB ( cos theta_(1) - cos theta_(2))`
Here, ` theta_(1) = theta_(2) = theta^(@)`
`rArr W = MB ( cos theta - cos theta ) = 0 `
Hence, option (d) is correct.
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