A copper wire of length 7 metre is bent to form a circular loop. If i current flows through the loop, find out the magnitude of magnetic moment of the loop.

Two identical wires each of length L are bent to form a circular loop and a square loop. If the same current i flows in the two wires, then the ratio of the magnetic inductions at the centre of the circular and square loops is :

A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m.If this square loop is changed to a circular loop and it carries the same current the magnitude of the magnetic dipole moment of circular loop will be

The magnitude of magnetic moment of the current loop in the figure is

A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m. if this square loop is changed to a circular loop and it carries the current, the magnitude of the magnetic dipole moment of circular loop will be :

The magnitude off magnetic moment of the current loop in the figure is

On meter length of wires carriers a constant current. The wire is bent to from a circular loop. The magnetic field at the centre of this loop is B . The same is now bent to form a circular loop of smaller radius to have four turns in the loop. The magnetic field at the centre of this loop B . The same is now bent to form a circular loop of smaller radius of have four turns in the loop. The magnetic field at the centre of this new loop is

The radius of a circular loop is r and a current i is flowing in it. The equivalent magnetic moment will be

A wire of length l carries a steady current. It is bent first to form a circular plane loop of one turn. The magnetic field at the centre of the loop is B. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same is