An electron is moving with a velocity of `5 xx 10^(7)` m/s in a magnetic field of `6 xx 10^(-4)` T perpendicular to it. What is the frequency? Also find the energy of electron in MeV.

Explanation

To solve the problem, we need to find the frequency of the electron moving in a magnetic field and its energy in MeV. Let's break it down step by step.

### Step 1: Identify the given data
- Velocity of the electron, \( V = 5 \times 10^7 \) m/s
- Magnetic field, \( B = 6 \times 10^{-4} \) T
- Charge of the electron, \( q = 1.6 \times 10^{-19} \) C
- Mass of the electron, \( m = 9.1 \times 10^{-31} \) kg

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