A rectangular loop carryinig current `I` is located near an infinite long straight conductor carrying current `I` as shown in the figure. The loop,

Explanation

The infinitely long wire which is carrying current `I_(1)` is providing non-uniform magnetic field for the square loop which is carrying current `I_(2) = 1 A` . Forces on the wire CD and EA are equal and opposite as the magnetic field due long wire is same at their location.

The wire AC and DA are present in uniform magnetic field `B_(1)" and "B_(2)` respectively,
So, they will experiences force as given below:
Force on wire AC is
`F_(AC) = I_(2)B_(1) a sin 90^(@)`
`I_(2) xx (mu_(0)I_(1))/(2 pi (0.1)) xx 20/100 xx 1 `
` = (1 xx 4 pi xx 10^(-7) xx 2)/(2 pi xx (0.1)) xx (0.2)`
` = 8 xx 10^(-7) N` , upwards
Force on wire DE is
`F_(DE) = I_(2) B_(2) a sin 90^(@) `
`I_(2) (mu_(0)I_(1))/(2 pi (0.3)) xx 0.2 xx 1 `
` = (1 xx 4 pi xx 10^(-7) xx 2 xx 0.2)/(2 pi xx 90.3)`
` = 2.67 xx 10^(-7) N`, downwards
The net force on the square loop of wire :
` F = F_(AC) - F_(DE)`
` = 8 xx 10^(-7) - 2.67 xx 10^(-7)`
`F = 5.34 xx 10^(-7) N`, upwards