A square shaped plane coil of area `100cm^2` of `200` turns carries a steady current of `5A`. It is placed in a uniform magnetic field of `0*2T` acting perpendicular to the plane of the coil. Calculate the torque on the coil when its plane makes an angle of `60^@` with the direction of the field. In which orientation will the coil be in stable equilibrium?

Explanation

Magnetic moment of coil :
` M = nIA`
` = 200 xx 5 xx 100 xx 10^(-4) Am^(2) = 10 Am^(2)`

Torque on this loop in magnetic field :
`tau = MB sin theta`
` = 10 xx 0.2 xx sin 30^(@)`
` = 2 xx 1/2`
` = 1 Nm`