Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is

Options

A. `250 Omega`
B. `25 Omega`
C. `40 Omega`
D. `500 Omega`

Explanation

To find the resistance of the galvanometer, we can use the relationship between current sensitivity (Si), voltage sensitivity (Sv), and the resistance of the galvanometer (Rg).

### Step-by-Step Solution:

1. **Understand the Given Values:**
- Current sensitivity (Si) = 5 div/mA = 5 div / (10^-3 A) = 5000 div/A
- Voltage sensitivity (Sv) = 20 div/V

2. **Use the Relationship Between Sensitivities:**
The relationship between current sensitivity, voltage sensitivity, and resistance is given by:
\[ R_g = \frac{S_i}{S_v} \]
where \( S_i \) is the current sensitivity and \( S_v \) is the voltage sensitivity.

3. **Substitute the Values:**
Substitute the values of \( S_i \) and \( S_v \) into the equation:
\[ R_g = \frac{5000 \, \text{div/A}}{20 \, \text{div/V}} \]

4. **Calculate the Resistance:**
\[ R_g = \frac{5000}{20} = 250 \, \Omega \]

5. **Final Answer:**
The resistance of the galvanometer is \( R_g = 250 \, \Omega \).