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A circular disc of radius 0.2 m is place...

A circular disc of radius `0.2 m` is placed in a uniform magnetic fied of induction `(1)/(pi) ((Wb)/(m^(2)))`
in such a way that its axis makes an angle of `60^(@)` with The magnetic flux linked with the disc is

A

`0.06` Wb

B

`0.08` Wb

C

`0.01` Wb

D

`0.02` Wb

Text Solution

Verified by Experts

The correct Answer is:
d
`:. " " phi_(B) = vecB * vecA = BA cos theta `
`= 1/pi xx pi r^(2) cos 60^(@)`
` = (0.2)^(2) xx 1/2 = 0.02 `Wb
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