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Two long conducting wires are placed par...

Two long conducting wires are placed parallel to each other at a distance d. Current carried by the wires is `i_(1)" and " i_(2)`. If F is the force acting between them, per unit of length, then which of the following statments is true?

A

F is proportional to `i_(1)i_(2)`

B

F is inversely proportional to d

C

F will be attraction if currents are in the same direction

D

F will be repulsive if currents are in the same direction

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To solve the problem regarding the force acting between two long parallel conducting wires carrying currents \( I_1 \) and \( I_2 \), we can follow these steps: ### Step 1: Understanding the Setup We have two infinitely long parallel wires separated by a distance \( d \). The first wire carries a current \( I_1 \) and the second wire carries a current \( I_2 \). ### Step 2: Magnetic Field Due to a Current-Carrying Wire The magnetic field \( B \) created by a long straight wire at a distance \( d \) from it is given by the formula: \[ B = \frac{\mu_0 I}{2 \pi d} \] where \( \mu_0 \) is the permeability of free space. ### Step 3: Magnetic Field at the Location of the Second Wire For wire 1 carrying current \( I_1 \), the magnetic field at the location of wire 2 (distance \( d \) away) is: \[ B_1 = \frac{\mu_0 I_1}{2 \pi d} \] The direction of this magnetic field can be determined using the right-hand rule. ### Step 4: Force on the Second Wire The force \( F \) on a current-carrying wire in a magnetic field is given by: \[ F = I \cdot L \cdot B \cdot \sin(\theta) \] For wire 2 carrying current \( I_2 \) in the magnetic field \( B_1 \), the force per unit length \( f \) is: \[ f = \frac{F}{L} = I_2 \cdot B_1 \] Since the angle \( \theta \) between the current direction and the magnetic field is \( 90^\circ \) (as they are perpendicular), we have \( \sin(90^\circ) = 1 \). ### Step 5: Substituting the Magnetic Field Substituting \( B_1 \) into the equation for force per unit length: \[ f = I_2 \cdot \frac{\mu_0 I_1}{2 \pi d} \] Thus, we can write: \[ f = \frac{\mu_0 I_1 I_2}{2 \pi d} \] ### Step 6: Analyzing the Nature of the Force - If the currents \( I_1 \) and \( I_2 \) are in the **same direction**, the force \( f \) is attractive. - If the currents are in **opposite directions**, the force is repulsive. ### Conclusion From our analysis, we can conclude: 1. The force \( F \) is proportional to \( I_1 \) and \( I_2 \). 2. The force \( F \) is inversely proportional to the distance \( d \). 3. The force is attractive if the currents are in the same direction. 4. The force is repulsive if the currents are in opposite directions. Thus, the correct statements are: - \( F \) is proportional to \( I_1 \times I_2 \). - \( F \) is inversely proportional to \( d \). - \( F \) is attractive if currents are in the same direction.

To solve the problem regarding the force acting between two long parallel conducting wires carrying currents \( I_1 \) and \( I_2 \), we can follow these steps: ### Step 1: Understanding the Setup We have two infinitely long parallel wires separated by a distance \( d \). The first wire carries a current \( I_1 \) and the second wire carries a current \( I_2 \). ### Step 2: Magnetic Field Due to a Current-Carrying Wire The magnetic field \( B \) created by a long straight wire at a distance \( d \) from it is given by the formula: \[ ...
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MODERN PUBLICATION-MOVING CHARGES AND MAGNETISM-COMPETITION FILE (C. MULTIPLE CHOICE QUESTIONS)
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