Find the hole density in doped silicon if at `27^(@)` c the electron density and hole density are equal nd equal to `3.0 xx10^(16)` on doping with arsenic electron density increases to `9xx10^(19) m^(-3)`

Explanation

To find the hole density in doped silicon, we can follow these steps:

### Step 1: Understand the given information
We know that at 27°C, the intrinsic carrier concentration (hole density and electron density) in pure silicon is given as:
- \( n_i = 3.0 \times 10^{16} \, \text{m}^{-3} \)

When doped with arsenic (a pentavalent dopant), the electron density increases to:
- \( n_e = 9.0 \times 10^{19} \, \text{m}^{-3} \)
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