The electron concentration and hole concentration in a semicoinductor are `6xx10^(13)` and `7xx10^(13) cm^(3)`
(i) what is the nature of semiconductor p type or n type
(ii) find the resistivity of the sample if electron mobility is 24000 and holw mobility is 200 `cm^(2) V^(-1)S^(-1)`

Explanation

To solve the given question, we will break it down into two parts: determining the nature of the semiconductor and calculating its resistivity.

### Part (i): Nature of the Semiconductor

1. **Identify Electron and Hole Concentrations**:
- Given:
- Electron concentration, \( n_e = 6 \times 10^{13} \, \text{cm}^{-3} \)
- Hole concentration, \( n_h = 7 \times 10^{13} \, \text{cm}^{-3} \)
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