In the current versus voltage characteristics of a diode minimum current of 1 mA is required for the knee voltage to be is connected in a cirucit the minimum value of R so that the voltage is above knee point is

Options

A. 3.7 k `omega`
B. 2.3 k `omega`
C. 5.2 k `omega`
D. 1.7 k `omega`

Explanation

Current in the circuit is
`I= (3V- 0.7 V)/( R)`
`rArr R= (2.3 V)/( 1mA) = (2.3 V)/( 10^(-3) A) = 2.3 xx 10^(3) Sigma `
`= 2.3 k Sigma`