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In the cirucit given below the knee volt...

In the cirucit given below the knee voltage for both the diodes is 0.5 v the current shupplied by the battery is

A

`5/20` A

B

`3/20` A

C

`5/10` A

D

`3/10` A

Text Solution

Verified by Experts

Here the diode in the upper branch is reverse biased and offers infinite resistance
`i=(5-0.5)/( 20 + 10) = (4.5)/( 30) = (3)/(20) A`
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