The contribution in the total current flowing through a semiconductor due to electrons and holes are `3/ 5` and `2/ 5` respectively. If the drift velocity of electrons is 2 times that of holes at this temperature, then the ratio of concentration of electrons and holes is

Options

A. `5//2`
B. `6//5`
C. `5//3`
D. `3//4`

Explanation

To solve the problem, we need to find the ratio of the concentration of electrons (nE) to the concentration of holes (nH) in a semiconductor based on the given contributions to the total current and the relationship between their drift velocities.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Contribution to total current from electrons (IE) = \( \frac{3}{5} \)
- Contribution to total current from holes (IH) = \( \frac{2}{5} \)
- Drift velocity of electrons (VD) = 2 × Drift velocity of holes (VDH)
...