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A light emitting diode (LED) has a volta...

A light emitting diode `(LED)` has a voltage drop of `2V` across it and passes a current of `10 mA`. When it operates with a `6V` battery through a limiting resistor `R`. The value of `R` is

A

40 k `omega`

B

4 k `omega`

C

200 `omega`

D

400 `omega`

Text Solution

Verified by Experts

`V_(L) = IR`
` 10 mA (R ) = 4`
`R= 0.4 xx 10^(3) = 400 Sigma`
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