A transistor is operated in common emitter configuration at `V_(c)=2 V` such that a change in the base current from `100 muA` to `200 muA` produces a change in the collector current from `5 mA` to `10 mA`. The current gain is

Options

A. 100
B. 150
C. 50
D. 75

Explanation

`Delta I_(B) = 200 - 100 mu A V_(0) = 2 V`
`beta = (DeltaI_(c ))/( Delta I_(B)) = (5 xx 10^(-3))/( 100 xx 10^(-8)) = 5 xx 50`