A n-p-n transisitor is connected in common emitter configuration in a given amplifier. A load resistance of `800 Omega` is connected in the collector circuit and the voltage drop across it is `0.8 V`. If the current amplification factor is `0.96` and the input resistance of the circuits is `192 Omega`, the voltage gain and the power gain of the amplifier will respectively be

Options

A. 3.69,3.84
B. 4,4
C. 4,3.69
D. 4,3.84

Explanation

given `V_(out) - I_(C ) R_(out)`
`beta= (I_(c ))/( I_(B)) = 0.96`
`V_(out) = I_(c ) (800)`
Voltage gain
`A_(V) = 4`
Power gain
`A_(p) = A_(v) ((I_(c ))/( I_(b))) = A, B =4 xx 0 .96 = 3.84`