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The currect voltage relation of diode is...

The currect voltage relation of diode is given by `1=(e^(1000 V//T)-1) mA`, where the applied voltage V is in volt and the temperature T is in degree Kelvin. If a student makes an error measuring `+-0.01 V` while measuring the current of `5 mA` at `300 K`, what will be error in the value of current in mA?

A

0.5 mA

B

0.05 mA

C

0.2 mA

D

0.02 mA

Text Solution

Verified by Experts

given `I=e^(1,000V(T))-1]mA`
`5mA = [e^(1,000 V(T)) -1) mA`
Differentiate 1 wrt v.
`Delta I= { exp ((1,000V)/( T)) xx (1)/(T) xx 1,000 }Delta V`
`=2 mA xx 10 (+- 0.01 ) = [120 mA ) (+- 0.01)`
`=2 xx 0 .1 = 0.2 mA`
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