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A common emitter transistor has a curr...

A common emitter transistor has a current amplification factor of 100 and is used as an amplifier the audio signal voltage across the collector resistance of 5 k `omega` is 5 V the base resistance is 2 k `omega` then

A

the input signal voltage is 0.01 v

B

the base curent is 10 `muA`

C

the input signal voltage is 0.02 v

D

the base current is 5 `muA`

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To solve the problem step by step, we will find the input signal voltage (Vin) and the base current (Ib) for the given common emitter transistor configuration. ### Given Data: - Current amplification factor (β) = 100 - Collector resistance (Rc) = 5 kΩ = 5000 Ω - Output voltage (Vout) = 5 V - Base resistance (Rb) = 2 kΩ = 2000 Ω ...
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