A ballot dancer is rotating about hyis own vertical axis on smooth horizontal floor with a time period `0.5 sec`. The dancer flods himself close to his axis of rotation due to which his radius of gyration decreases by `20%`, then his new time period is

A ballet dancer is rotating about his own vertical axis at an angular velocity 100 rpm on smooth horizontal floor. The ballet dancer folds himself close to his axis of rotation by which is moment of inertia decreases to half of initial moment of inertia then his final angular velocity is

A ballet dancer is rotating at angular velocity omega on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by 1//4^(th) of his initial radius of gyration, his final angular velocity is

A ballet dancer is rotating about his own vertical axis. Without external torque if his angular velocity is doubled then his rotational kinetic energy is

A ballet dancer is rotating about his own vertical axis on smooth horizontal floor. I, omega, L, E are moment of inertia, angular velocity, angular momentum, rotational kinetic energy of ballet dancer respectively. If ballet dancer stretches himself away from his axis of rotation, then

A ballet dancer spins about a vertical axis at 120 rpm with arms outstretched. With her arms folded, the moment of inertia about the axis of rotation decreases by 40%. Calculate the new rate of rotation.

A dancer is rotating on smooth horizontal floor with an angular momentum L The dancer folds her hands so that her moment of inertia decreases by 25%. The new angular momentum is

A ballet dancer spins about a vertical axis at 120 rpm with arms out stretched. With her arms fold the moment of inertia about the axis of rotation decreases by 40% . What is new rate of revolution?

A ballet dancer spins about a vertical axis at 90 rpm with arms outstretched. With the arms folded, the moment of inertia about the same axis of rotation changes to 75 %. Calculate the new speed of rotation.