[" 3) "4" a "],[" ABC is a triangle."D" is the middle point of "BC" .If "AD" is perpendicular to "AC" ,then cosA "cos C=]

ABC is a triangle. D is the middle point of BC. If AD is perpendicular to AC, The value of cos A cos C , is

ABC is a triangle. D is the middle point of BC. If AD is perpendicular to AC, The value of cos A cos C , is

In triangle ABC,D is the midpoint of BC and AD is perpendicular to AC. Then cos A.cos C=

In triangle ABC, D is mid point of BC, if 'AD' is perpendicular to 'AC then cos A cos C

In a Delta ABC , if D is the mid point of BC and AD is perpendicular to AC , then cos B =

ABC is a triangle and D is the middle point of BC. If AD is perpendicular to AC, then prove that cos A . cos C =(2(c^(2)-a^(2)))/(3ac)

In a Delta ABC, if D is the mid point of BC and AD is perpendicular to AC, then cos B=

In a DeltaABC , if D is the middle point of BC and AD is perpendicular to AC, then cos C equals

ABC is a triangle and D is the middle point of BC. If AD is perpendicular to AC, prove that, cosA cos C =(2(c^(2)-a^(2))/(3ca))