Oxygen is prepared by the catalytic decomposition of potassium chlorate (`KClO_(3)`). Decomposition of potassium chlorate gives potassium chloride (KCl) and oxygen (`O_(2)`). If 2.4 mol of oxygen is needed for an experiment, how many grams of potassium chlorate must be decomposed ?

Explanation

To find out how many grams of potassium chlorate (KClO₃) must be decomposed to produce 2.4 moles of oxygen (O₂), we can follow these steps:

### Step 1: Write the balanced chemical equation for the decomposition of potassium chlorate.
The balanced equation for the decomposition of potassium chlorate is:
\[ 2 \text{KClO}_3 (s) \rightarrow 2 \text{KCl} (s) + 3 \text{O}_2 (g) \]

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