Calculate the amount of lime `Ca(OH)_2` required to remove the hardness of 60,000 litres of well water containing 16.2 g of calcium bicarbonate per hundred litre. (Atomic masses Ca = 40, C = 12, O = 16, H = 1)

Explanation

To calculate the amount of lime \( \text{Ca(OH)}_2 \) required to remove the hardness of 60,000 liters of well water containing 16.2 g of calcium bicarbonate per 100 liters, we will follow these steps:

### Step 1: Calculate the total amount of calcium bicarbonate in 60,000 liters of water.

Given that there are 16.2 grams of calcium bicarbonate in every 100 liters, we can find the total amount in 60,000 liters using the following calculation:

\[
\text{Total mass of } \text{Ca(HCO}_3\text{)}_2 = \left( \frac{16.2 \text{ g}}{100 \text{ L}} \right) \times 60,000 \text{ L}
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