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A solution has been prepared by dissolvi...

A solution has been prepared by dissolving 60 g of methyI alcohol in 120 g of water. What are the mole fraction of methyI alcohol and water ?

Text Solution

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Mass of methanol = 60 g
Moles of methanol `=60/32 = 1.875`
(Molar mass = 32)
Mass of water = 120g
Moles of water `=120/18 = 6.667`
(Molar mass = 18)
Total number of moles = 1.875 + 6.667
= 8.542
Mole fraction of methanol `=(1.875)/(8.542) = 0.220`
Mole fraction of water `=6.667/8.542 = 0.780`
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