Calculate the concentration of nitric acid in moles per litre in a sample which has a density `1.41 g //mL` and the mass percent of nitric acid in it being `69%`.

Explanation

69 mass percent of nitric acid means that 69 g of`HNO_(3)` are present in 100 g of solution.
Volume of solution `=("Mass")/("density") = (100 g)/(1.41 g mL^(-1))`
= 70.92 mL
Moles of `HNO_(3) = 69/63`
`therefore` Molarity `=("Moles of"HNO_(3))/("Volume of solution in mL") xx 1000`
`=(69//63)/(70.92) xx 1000 = 15.44` M