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The density of 3M solution of NaCL is 1....

The density of 3M solution of NaCL is 1.25 g`mL^(-1)`. Calculate molality of the solution.

Text Solution

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3 M solution means that 3 moles of NaCl are present in 1 L solution.
Mass of NaCl in 1 L solution = `3 xx 58.5`
= 175.5 g
(`therefore` Molecular mass of NaCl = 58.5)
Density of solution = `1.25 g mL^(-1)`
Mass of 1 L solution `=1000 xx 1.25 = 1250` g
Mass of water in solution `=1250 - 175.5`
=1074.5 g
Molality `=("Moles of solute")/("Mass of solvent in g") xx 1000`
`=3/(1074.5) xx 1000`
= 2.79 m
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