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250 ml of 0.5 M sodium sulphate (Na(2)SO...

250 ml of 0.5 M sodium sulphate (`Na_(2)SO_(4)`) solution are added to an aqueous solution containing 10.0g of `BaCl_(2)` resulting in the formation of white precipitate of `BaSO_(4)` . How many moles and how many grams of barium sulphate will be obtained ?

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To solve the problem step by step, we will follow these steps: ### Step 1: Calculate the number of moles of Sodium Sulfate (Na₂SO₄) Given: - Volume of Na₂SO₄ solution = 250 mL = 0.250 L - Molarity (M) of Na₂SO₄ = 0.5 M ...
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