a) Calculate the number of chloride of 0.01 M 100 ml `AlCl_(3)` solution.
(b) What will be the change in number of chloride ions if the solution is diluted by 100 mL water?

Explanation

To solve the problem step-by-step, we will break it down into two parts as given in the question.

### Part (a): Calculate the number of chloride ions in 0.01 M AlCl₃ solution (100 mL)

1. **Calculate the moles of AlCl₃ in the solution**:
- Molarity (M) = Moles of solute / Volume of solution in liters
- Given: Molarity (M) = 0.01 M, Volume = 100 mL = 0.1 L
- Rearranging the formula to find moles:
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