Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

Explanation

0.375 M aqueous solution means that 0.375 mol of sodium acetate are present I 1000 mL of solution. 500 mL of the solution should contain sodium acetate.
`=0.375/2` mol
Molar mass of sodium acetate = 82.0245 g `mol^(-1)`
Mass of sodium acetate required `=0.375/2 xx 82.0245`
=15.38 g
Alternatively, it may be solved as:
Molarity `=(("Mass of sodium acetate")/(82.0245))/500 xx 1000`
`therefore` Mass of sodium acetate `=(0.375 xx 82.0245 xx 500)/1000`
= 15.38 g