One mole of any substance contains `6.022 xx 10^(23)` atoms/molecules. Number of molecules of `H_(2)SO_(4)` present in 100 mL of 0.02 M `H_(2)SO_(4)` solution is :

Options

A. `12.044 xx 10^(20)` molecules
B. `6.022 xx 10^(23)` molecules
C. `1 xx 10^(23)` molecules
D. `12.044 xx 10^(23)` molecules

Answer

A

Explanation

Moles of `H_(2)SO_(4)=0.02/1000 xx 100 = 0.02` mol
Molecules `=0.002 xx 6.022 xx 10^(23)`
`=12.044 xx 10^(20)`