16 g of oxygen have same number of molecules as in :

Options

A. 16 g of CO
B. 28 of `N_(2)`
C. 14 g of `N_(2)`
D. 2.0 g of `H_(2)`

Answer

C

Explanation

16 g of CO `=16/28 = 0.57` mol = 0.57 `N_(A)` molecules.
`28 g N_(2) = 28/28 = 1.0` mol `=N_(A)` molecules
14 g `N_(2)=14/28 = 0.5` mol `=0.5 N_(A)` molecules
1.0 g `H_(2) = 1.0/2 = 0.5` mol = 0.5 `N_(A)` molecules.