Lithium oxide is used to remove water from air according to the following reaction:
`Li_(2)O(s) + H_(2)O(g) to 2LiOH(s)`
90 kg of water is to be removed and 45 kg of `Li_(2)O` is available.
Which reactant is the limiting reactant?

Explanation

To determine the limiting reactant in the reaction between lithium oxide (Li₂O) and water (H₂O), we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced chemical equation for the reaction is:
\[ \text{Li}_2\text{O (s)} + \text{H}_2\text{O (g)} \rightarrow 2\text{LiOH (s)} \]

### Step 2: Calculate the number of moles of water (H₂O)
We are given that 90 kg of water needs to be removed. First, we convert this mass into grams:
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