0.6 g of carbon was burnt in the air to form `CO_(2)`. The number of molecules of `CO_(2)` introduced into the will be : `C+O_(2)toCO_(2)`

Answer

B

Explanation

`C + O_(2) to CO_(2)`
12 g of C gives `CO_(2) = 44g`
0.6 g of C will give `CO_(2) = 44/12 xx 0.6 = 2.2`g
Moles of `CO_(2) = 2.2/44 = 0.05`
No. of molecules = `0.05 xx 6.02 xx 10^(23)= 3.01 xx 10^(22)`