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The number of atoms in 4.25 g of NH(3) i...

The number of atoms in `4.25` g of `NH_(3)` is approximately

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The correct Answer is:
D
Moles of `NH_(3) = 4.25/17`
No. of atoms `=(4.25)/17 xx 6.02 xx 10^(23) xx 4`
`=6.02 xx 10^(23)`
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