How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

Answer

C

Explanation

`PbO + 2HCl to PbCl_(2) + H_(2)O`
Molar mass of PbO =207 + 16 = 223 `g mol^(-1)`
Moles of PbO `=6.5/223 = 0.029` mol
Moles of HCl `=3.2/(36.5) = 0.088` mol
1 mol of PbO reacts with 2 mol of HCl
`therefore PbO` is a limiting reagent
0.029 mol of PbO will produce `PbCl_(2) = 0.029` mol