Volume occupied by one molecule of water (density = 1 g `cm^(-3)`)

Answer

B

Explanation

Mass of 1 molecule of water `=18/(6.022 xx 10^(23))`g
Volume `=(18 g)/(6.022 xx 10^(23) xx 1g//cm^(3)) = 3.0 xx 10^(-23) cm^(3)`