For reaction `A+2BtoC`. The amount of C formed by starting the reaction with 5 mole of A and 8 mole of B is :

Options

A. 5 moles
B. 8 moles
C. 16 moles
D. 4 moles

Answer

D

Explanation

`underset(1 "mol")A + underset(2 "mol")(2B) to underset("1 mol")C`
8 moles of B require 4 moles of A. Therefore, limiting reagent is B.
2 moles of B give 1 mole of C
`therefore 8` moles of B give `=1/2 xx 8=4` moles of C.