In which case is the number of molecules of water maximum?

Options

A. 18 mL of water
B. 0.18 g of water
C. 0.00224 L of water vapours at 1 atm and 273 K
D. `10^(-3)` mol of water.

Answer

A

Explanation

18 mL of water has maximum number of molecules.
18 mL of water `=18 xx 1 g//mL = 18 g`
Molecules of water `=18/18 xx N_(A) = N_(A)`
(b) 0.18 g of water
molecules of water `=0.18/18 xx N_(A) = N_(A)`
( c ) Moles of water `=(0.00224 L)/(22.4) = 0.0001`
Molecules of water = 0.0001 `xx N_(A) = 0.0001 xx N_(A)`
(d) `10^(-3)` mol of water
Molecules of water `=10^(-3) xx N_(A) = 0.001 N_(A)`