You are given 500 mL of 2N HCl and 500 mL of 5N HCl. What will be the maximum volume of 3 M HCl that you can make from these two solutions ?

Options

A. 250 mL
B. 500 mL
C. 750 mL
D. 1000 mL

Answer

C

Explanation

Maximum volume of 3 M HCl solution can be prepared by taken 500 mL of 2 N HCl and x mL of 5 N HCl so that total volume becomes (500 + x) `xx 3`
`1000 + 5x = 1500 + 3x`
`2x = 500` or x = 250 mL
Thus, maximum volume of 3 M solution formed.
= 500 + 250 = 750 mL