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8g of NaOH is dissolved in 18g of H(2)O....

8g of NaOH is dissolved in 18g of `H_(2)O`. Mole fraction of NaOH in solution and molality (in mol `kg^(-1)`) of the solutions respectively are:

A

0.167, 11.11

B

0.2, 22.20

C

0.2, 11.11

D

0.167, 22.20

Text Solution

Verified by Experts

The correct Answer is:
A
moles of NaOH `=8/40 = 0.2` mol
Moles of water `=18/18 = 1.0` mol
Mole fraction of NaOH `=0.2/(0.2 + 1.0) = 0.167` Molality `=(0.2 xx 1000)/18 = 11.11` m
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