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From the following nuclei select the iso...

From the following nuclei select the isotopes and isobars :
`""_(92)^(238)U, ""_(90)^(234)Th, ""_(92)^(234)U, ""_(91)^(234)Pa` .

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To determine the isotopes and isobars from the given nuclei, we need to understand the definitions: 1. **Isotopes**: Isotopes are nuclei that have the same atomic number (same number of protons) but different mass numbers (different number of neutrons). 2. **Isobars**: Isobars are nuclei that have the same mass number (same total number of protons and neutrons) but different atomic numbers (different number of protons). Now, let's analyze the given nuclei: 1. **Uranium-238**: \( _{92}^{238}U \) - Atomic Number (Z) = 92 - Mass Number (A) = 238 2. **Thorium-234**: \( _{90}^{234}Th \) - Atomic Number (Z) = 90 - Mass Number (A) = 234 3. **Uranium-234**: \( _{92}^{234}U \) - Atomic Number (Z) = 92 - Mass Number (A) = 234 4. **Protactinium-234**: \( _{91}^{234}Pa \) - Atomic Number (Z) = 91 - Mass Number (A) = 234 Now, let's identify isotopes and isobars: ### Step 1: Identify Isotopes - **Uranium-238** and **Uranium-234**: Both have the same atomic number (92), thus they are isotopes. - **Uranium-234** and **Protactinium-234**: They have different atomic numbers (92 for U and 91 for Pa), so they are not isotopes. ### Step 2: Identify Isobars - **Thorium-234** and **Uranium-234**: Both have the same mass number (234), thus they are isobars. - **Thorium-234** and **Protactinium-234**: Both have the same mass number (234), thus they are isobars. - **Uranium-238** does not match with any other nucleus in terms of mass number. ### Final Results - **Isotopes**: \( _{92}^{238}U \) and \( _{92}^{234}U \) - **Isobars**: \( _{90}^{234}Th \), \( _{91}^{234}Pa \), and \( _{92}^{234}U \) ### Summary - Isotopes: \( _{92}^{238}U \) and \( _{92}^{234}U \) - Isobars: \( _{90}^{234}Th \), \( _{91}^{234}Pa \), and \( _{92}^{234}U \)
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""_(92)^(235)U, ""_(92)^(238)U and ""_(92)^(239)U are

find the number of elements which are iosfiapher of ""_(92)U^(238) ""_(93)Th^(234),""_(90)TH^(232),""_(93)Np^(237),""_(96)Cm^(247)

Calculate the energy released in MeV in the following nuclear reaction : ._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u Mass of ._(90)^(238)Th=234.043630 u Massof ._(2)^(4)He=4.002600 u 1u = 931.5 MeV//c^(2)]

Find the kinetic energy of emitted a-particles in the following nuclear reaction: ""_(94)Pu^(238) to ""_(92)U^(234) + ""_(2)He^(4) m(Pu^(238)) = 238.04954 amu m(U^(234)) = 234.04096 amu m(""_(2)He^(4)) = 4.002603 amu

Determine the number of protons and neutrons in ""_(92)U^(238) and ""_(90)Th^(234) .

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