Species X with mass number 37 contains 11.1 % more neutrons as compared to electrons , then what is the incorrect representation of element x?

Answer

`""_(17)^(87)Cl^(-)`

Explanation

Since it carries -1 charge, it will have one electron more than the number of protons.
Let number of electrons = x
No. of proton = `x - 1`
No. of neutrons = `x + x xx (11.1)/(100) = 1.111 x`
Now, `x - 1 + 1.111 x = 37`
or ,`2.111 x = 38`
`x = 18`
No. of `e = 18`
No. of `p = 18-1 = 17`
No. of `n = 35 - 17 = 18`
Symbol `""_(17)^(35)Cl^(-)`.