The velocity associated with a proton moving in a potential difference of `1000 V` is `4.37xx10^(-5)ms^(-1)`. If the hockey ball of mass 0.1 kg is moving with the velocity, calcuate the wavelength associated with this.

Answer

`1.52 xx 10^(-38) m`

Explanation

`lambda = h/(mv)`
`= (6.63 xx 10^(-34))/(0.1 xx 4.37 xx 10^(-5)) = 1.52 xx 10^(-38) m`.