For each of the following pair of hydrogen orbitals, indicate which is higher in erergy :
`(i) 1s, 2s " " (ii) 2p, 3p`
`(iii) 3d_(xy) , 3d_(yz) " " (iv) 3s, 3d`
`(v) 4f, 5s. `

Explanation

To determine which orbital is higher in energy for each pair of hydrogen orbitals, we can use the principle that the energy of hydrogen orbitals depends primarily on the principal quantum number (n). The formula for the energy of an electron in a hydrogen atom is given by:

\[ E_n = -\frac{E_0 Z^2}{n^2} \]

Where:
- \( E_0 \) is a constant,
- \( Z \) is the atomic number (which is 1 for hydrogen),
- \( n \) is the principal quantum number.
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