If the diameter of a carbon atom is `0.15 nm`, calculate the number of carbon atom which can be placed side by side in a straight line length of scale of length `20 cm` long.

Explanation

A carbon atom covers length = diameter of atom = 0.15 nm.
`= 0.15 xx 10^(-9) xx 10^2 cm`
`:. ` No. of carbon atoms which can be placed on 20 cm length.
`= (20)/(0.15 xx 10^(-9) xx 10^2) = 1.33 xx 10^9`.