Home
Class 11
CHEMISTRY
Calculate the internal energy change for...

Calculate the internal energy change for each of the following processes:
(i) A system absorbs 428 J of heat and does work equivalent to 286 J on its surroundings.
(ii) 62 J of work is done on the system and 128 J of heat is transferred to the surroundings.

Text Solution

AI Generated Solution

To calculate the internal energy change for the given processes, we will use the First Law of Thermodynamics, which states: \[ \Delta U = Q + W \] where: - \(\Delta U\) is the change in internal energy, ...
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Practice Problems|65 Videos
  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Advanced Level Problems|15 Videos
  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise Unit Practice Test|13 Videos

Similar Questions

Explore conceptually related problems

A system absorbs 600 J of heat and does a work of 200 J on its surroundings. delta E of system is

A system absorbs 600J of heat and work equivalent to 300J on its surroundings. The change in internal energy is:

A system absorb 600 J of heat and work equivalent to 300 J on its surroundings. The change in internal energy

A system absorbs 800 J of heat and system works equivalent to 900 J by expanding. The value of Delta U for the system is

A system absorbs 6 kJ of heat and does 1.5 kJ of work on its surroundings. The charge in internal energy is ………

A system absorbs 920 J of heat and does work. The change in internal energy (Delta U) for the process is 460 J. The work done by the system is

During a process, a system abdorbs 710J of heat and does work. The change in DeltaU for the process is 460J . What is the work done by the system?

A system absorbs 920 J of heat and does work. The change in internal energy (DeltaU) for the process is 460 J. The work done by the system is ________ .