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Calculate the number of `KJ` necessary to raise the temperature of `60.0 g` of aluminium from `35^(@)` to `55^(@)C`. Molar heat capcacity of `Al` is `24 J mol^(-1)K^(-1)` (Answer in Joules)

Text Solution

Verified by Experts

The correct Answer is:
10668

Mass of aluminium = 60 g
Rise in temperature `DeltaT = 55 - 35 = 20^(@)C`
Molar heat capacity of AI = `24J mol^(-1) K^(-1)`
Specific heat capacity of AI `=(24)/(27) = 0.889 J g^(-1)J^(-1)`
Energy required = `m xx C xx DeltaT`
` = 60 xx 0.889 xx 20 `
`= 10668 J or 1.07kJ`
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