Calculate the enthalpy change for the reaction
`CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l)`
The enethalpy of formation of `CH_(4)(g),CO_(2)(g)` and `H_(2)O(l)` are -74.8 kJ `mol^(-1)`, -393.5 kJ `mol^(-1)` and `-285.8 kJ mol^(-1)` respectively.

Explanation

To calculate the enthalpy change for the reaction:

\[ \text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(l) \]

we will use the standard enthalpy of formation values provided for each substance involved in the reaction.

### Step 1: Write the equation for the enthalpy change of the reaction

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