Enthalpies of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` are `-110, -393, 81` and `9.7 kJmol^(-1)` respectively. Calculate `Delta_(r)H` for the reaction:
`N_(2)O_(4)(g) + 3CO(g) to N_(2)O(g) + 3CO_(2)(g)`.

Explanation

To calculate the enthalpy change (Δ_rH) for the reaction:

\[ \text{N}_2\text{O}_4(g) + 3\text{CO}(g) \rightarrow \text{N}_2\text{O}(g) + 3\text{CO}_2(g) \]

we will use the enthalpies of formation provided for each compound. The general formula for calculating the enthalpy change of a reaction using enthalpies of formation is:

\[
\Delta_rH = \sum \Delta H_f^{\text{products}} - \sum \Delta H_f^{\text{reactants}}
...