Calculate the enthalpy of formation of benzene represented by the following reaction:
` 6C(s) + 3H_(2)(g) to C_(6)H_(6)(l)`
The standard enthalpy of combustion of benzene is -3266.0 kJ and standard enthalpies of formation of `CO_(2)(g)` and `H_(2)O(l)` are - 393.1 and -286.0 kJ respectively.

Explanation

To calculate the enthalpy of formation of benzene (C₆H₆) from the given reaction, we can use Hess's law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps of the reaction.

### Step-by-Step Solution:

1. **Write the combustion reaction of benzene**:
The combustion of benzene can be represented as:
\[
C_6H_6(l) + 7.5 O_2(g) \rightarrow 6 CO_2(g) + 3 H_2O(l)
...