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Calculate the standard Gibbs free energy...

Calculate the standard Gibbs free energy change from the free energies of formation data for the following reaction:
`C_(6)H_(6)(l) +(15)/(2)O_(2)(g) rarr 6CO_(2)(g) +3H_(2)O(g)`
Given that `Delta_(f)G^(Theta) =[C_(6)H_(6)(l)] = 172.8 kJ mol^(-1)`
`Delta_(f)G^(Theta)[CO_(2)(g)] =- 394.4 kJ mol^(-1)`
`Delta_(f)G^(Theta) [H_(2)O(g)] =- 228.6 kJ mol^(-1)`

Text Solution

Verified by Experts

`DeltaG = Sigma Delta_(f)G^(@)("products") - Sigma Delta_(f)G^(@)("reactants")` = `{6Delta_(f)G^(@)[CO_(2)(g)] + 3 Delta_(f)G^(@) [ H_(2)O(g)]} - {Delta_(f)G^(@) {C_(6)H_(6)(l)] + (15)/(2)Delta_(f)G^(@) [ O_(2)(g)]}`
` = { (6 xx -394.4 ) + 3 xx (-228.6)} - { 172.8 + 0} = - 3225 kJ mol^(-1)`
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